7q-5=3q+27

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Solution for 7q-5=3q+27 equation: 



7q-5=3q+27

We move all terms to the left:

7q-5-(3q+27)=0

We get rid of parentheses

7q-3q-27-5=0

We add all the numbers together, and all the variables

4q-32=0

We move all terms containing q to the left, all other terms to the right

4q=32

q=32/4

q=8

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