7q-5=3q+27

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Solution for 7q-5=3q+27 equation:



7q-5=3q+27
We move all terms to the left:
7q-5-(3q+27)=0
We get rid of parentheses
7q-3q-27-5=0
We add all the numbers together, and all the variables
4q-32=0
We move all terms containing q to the left, all other terms to the right
4q=32
q=32/4
q=8

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