7r-3(2r-5)+5+3r=4r+20

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Solution for 7r-3(2r-5)+5+3r=4r+20 equation: 


Simplifying
7r + -3(2r + -5) + 5 + 3r = 4r + 20

Reorder the terms:
7r + -3(-5 + 2r) + 5 + 3r = 4r + 20
7r + (-5 * -3 + 2r * -3) + 5 + 3r = 4r + 20
7r + (15 + -6r) + 5 + 3r = 4r + 20

Reorder the terms:
15 + 5 + 7r + -6r + 3r = 4r + 20

Combine like terms: 15 + 5 = 20
20 + 7r + -6r + 3r = 4r + 20

Combine like terms: 7r + -6r = 1r
20 + 1r + 3r = 4r + 20

Combine like terms: 1r + 3r = 4r
20 + 4r = 4r + 20

Reorder the terms:
20 + 4r = 20 + 4r

Add '-20' to each side of the equation.
20 + -20 + 4r = 20 + -20 + 4r

Combine like terms: 20 + -20 = 0
0 + 4r = 20 + -20 + 4r
4r = 20 + -20 + 4r

Combine like terms: 20 + -20 = 0
4r = 0 + 4r
4r = 4r

Add '-4r' to each side of the equation.
4r + -4r = 4r + -4r

Combine like terms: 4r + -4r = 0
0 = 4r + -4r

Combine like terms: 4r + -4r = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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