7r-5r/2=5/r

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Solution for 7r-5r/2=5/r equation: 


D( r )

r = 0

r = 0

r = 0

r in (-oo:0) U (0:+oo)

7*r-((5*r)/2) = 5/r // - 5/r

7*r-((5*r)/2)-(5/r) = 0

7*r+(-5/2)*r-5*r^-1 = 0

9/2*r^1-5*r^-1 = 0

(9/2*r^2-5*r^0)/(r^1) = 0 // * r^2

r^1*(9/2*r^2-5*r^0) = 0

r^1

(9/2)*r^2-5 = 0

(9/2)*r^2-5 = 0

DELTA = 0^2-(-5*4*(9/2))

DELTA = 90

DELTA > 0

r = (90^(1/2)+0)/(2*(9/2)) or r = (0-90^(1/2))/(2*(9/2))

r = (1*10^(1/2))/3 or r = (-10^(1/2))/3

r in { (-10^(1/2))/3, (1*10^(1/2))/3} 

r in { (-10^(1/2))/3, (1*10^(1/2))/3 }

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