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7r^2+15r+2=0
a = 7; b = 15; c = +2;
Δ = b2-4ac
Δ = 152-4·7·2
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-13}{2*7}=\frac{-28}{14} =-2 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+13}{2*7}=\frac{-2}{14} =-1/7 $
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