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7s^2+56s+49=0
a = 7; b = 56; c = +49;
Δ = b2-4ac
Δ = 562-4·7·49
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-42}{2*7}=\frac{-98}{14} =-7 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+42}{2*7}=\frac{-14}{14} =-1 $
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