7t+(2t+1)+3f=55

Solution for 7t+(2t+1)+3f=55 equation:

Simplifying
7t + (2t + 1) + 3f = 55

Reorder the terms:
7t + (1 + 2t) + 3f = 55

Remove parenthesis around (1 + 2t)
7t + 1 + 2t + 3f = 55

Reorder the terms:
1 + 3f + 7t + 2t = 55

Combine like terms: 7t + 2t = 9t
1 + 3f + 9t = 55

Solving
1 + 3f + 9t = 55

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 3f + -1 + 9t = 55 + -1

Reorder the terms:
1 + -1 + 3f + 9t = 55 + -1

Combine like terms: 1 + -1 = 0
0 + 3f + 9t = 55 + -1
3f + 9t = 55 + -1

Combine like terms: 55 + -1 = 54
3f + 9t = 54

Add '-9t' to each side of the equation.
3f + 9t + -9t = 54 + -9t

Combine like terms: 9t + -9t = 0
3f + 0 = 54 + -9t
3f = 54 + -9t

Divide each side by '3'.
f = 18 + -3t

Simplifying
f = 18 + -3t