7t+3(t-2)=8(t-3)-10

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Solution for 7t+3(t-2)=8(t-3)-10 equation:



7t+3(t-2)=8(t-3)-10
We move all terms to the left:
7t+3(t-2)-(8(t-3)-10)=0
We multiply parentheses
7t+3t-(8(t-3)-10)-6=0
We calculate terms in parentheses: -(8(t-3)-10), so:
8(t-3)-10
We multiply parentheses
8t-24-10
We add all the numbers together, and all the variables
8t-34
Back to the equation:
-(8t-34)
We add all the numbers together, and all the variables
10t-(8t-34)-6=0
We get rid of parentheses
10t-8t+34-6=0
We add all the numbers together, and all the variables
2t+28=0
We move all terms containing t to the left, all other terms to the right
2t=-28
t=-28/2
t=-14

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