7t-(3t+4)=-2(2t-1)+10

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Solution for 7t-(3t+4)=-2(2t-1)+10 equation: 



7t-(3t+4)=-2(2t-1)+10

We move all terms to the left:

7t-(3t+4)-(-2(2t-1)+10)=0

We get rid of parentheses

7t-3t-(-2(2t-1)+10)-4=0



We calculate terms in parentheses: -(-2(2t-1)+10), so:

-2(2t-1)+10

We multiply parentheses

-4t+2+10

We add all the numbers together, and all the variables

-4t+12

Back to the equation:

-(-4t+12)



We add all the numbers together, and all the variables

4t-(-4t+12)-4=0

We get rid of parentheses

4t+4t-12-4=0

We add all the numbers together, and all the variables

8t-16=0

We move all terms containing t to the left, all other terms to the right

8t=16

t=16/8

t=2

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