7t-2-(3t+1)=-3(1+-3t)

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Solution for 7t-2-(3t+1)=-3(1+-3t) equation: 



7t-2-(3t+1)=-3(1+-3t)

We move all terms to the left:

7t-2-(3t+1)-(-3(1+-3t))=0

We add all the numbers together, and all the variables

7t-(3t+1)-(-3(-3t))-2=0

We get rid of parentheses

7t-3t-(-3(-3t))-1-2=0



We calculate terms in parentheses: -(-3(-3t)), so:

-3(-3t)

We multiply parentheses

9t

Back to the equation:

-(9t)



We add all the numbers together, and all the variables

-5t-3=0

We move all terms containing t to the left, all other terms to the right

-5t=3

t=3/-5

t=-3/5

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