7t/2t+2=4+7t

Solution for 7t/2t+2=4+7t equation:

7t/2t+2=4+7t

We move all terms to the left:

7t/2t+2-(4+7t)=0


Domain of the equation: 2t!=0

t!=0/2

t!=0

t∈R


We add all the numbers together, and all the variables

7t/2t-(7t+4)+2=0

We get rid of parentheses

7t/2t-7t-4+2=0

We multiply all the terms by the denominator


7t-7t*2t-4*2t+2*2t=0

Wy multiply elements

-14t^2+7t-8t+4t=0

We add all the numbers together, and all the variables

-14t^2+3t=0

a = -14; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-14)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-14}=\frac{-6}{-28}
=3/14
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-14}=\frac{0}{-28}
=0
$