7t/2t+2=4+7t

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Solution for 7t/2t+2=4+7t equation:



7t/2t+2=4+7t
We move all terms to the left:
7t/2t+2-(4+7t)=0
Domain of the equation: 2t!=0
t!=0/2
t!=0
t∈R
We add all the numbers together, and all the variables
7t/2t-(7t+4)+2=0
We get rid of parentheses
7t/2t-7t-4+2=0
We multiply all the terms by the denominator
7t-7t*2t-4*2t+2*2t=0
Wy multiply elements
-14t^2+7t-8t+4t=0
We add all the numbers together, and all the variables
-14t^2+3t=0
a = -14; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-14)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-14}=\frac{-6}{-28} =3/14 $
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-14}=\frac{0}{-28} =0 $

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