7u+3(u+4)=-28

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Solution for 7u+3(u+4)=-28 equation: 



7u+3(u+4)=-28

We move all terms to the left:

7u+3(u+4)-(-28)=0

We add all the numbers together, and all the variables

7u+3(u+4)+28=0

We multiply parentheses

7u+3u+12+28=0

We add all the numbers together, and all the variables

10u+40=0

We move all terms containing u to the left, all other terms to the right

10u=-40

u=-40/10

u=-4

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