7u+3(u+4)=-28

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Solution for 7u+3(u+4)=-28 equation:



7u+3(u+4)=-28
We move all terms to the left:
7u+3(u+4)-(-28)=0
We add all the numbers together, and all the variables
7u+3(u+4)+28=0
We multiply parentheses
7u+3u+12+28=0
We add all the numbers together, and all the variables
10u+40=0
We move all terms containing u to the left, all other terms to the right
10u=-40
u=-40/10
u=-4

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