7u+3-2(-2u-3)=3(u-1)

Solution for 7u+3-2(-2u-3)=3(u-1) equation:

7u+3-2(-2u-3)=3(u-1)

We move all terms to the left:

7u+3-2(-2u-3)-(3(u-1))=0

We multiply parentheses

7u+4u-(3(u-1))+6+3=0


We calculate terms in parentheses: -(3(u-1)), so:

3(u-1)

We multiply parentheses

3u-3

Back to the equation:

-(3u-3)


We add all the numbers together, and all the variables

11u-(3u-3)+9=0

We get rid of parentheses

11u-3u+3+9=0

We add all the numbers together, and all the variables

8u+12=0

We move all terms containing u to the left, all other terms to the right

8u=-12

u=-12/8

u=-1+1/2