7u-4+2(3u+4)=-5(u+1)

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Solution for 7u-4+2(3u+4)=-5(u+1) equation: 



7u-4+2(3u+4)=-5(u+1)

We move all terms to the left:

7u-4+2(3u+4)-(-5(u+1))=0

We multiply parentheses

7u+6u-(-5(u+1))+8-4=0



We calculate terms in parentheses: -(-5(u+1)), so:

-5(u+1)

We multiply parentheses

-5u-5

Back to the equation:

-(-5u-5)



We add all the numbers together, and all the variables

13u-(-5u-5)+4=0

We get rid of parentheses

13u+5u+5+4=0

We add all the numbers together, and all the variables

18u+9=0

We move all terms containing u to the left, all other terms to the right

18u=-9

u=-9/18

u=-1/2

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