7u-5+2(4u+5)=-3(u+3)

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Solution for 7u-5+2(4u+5)=-3(u+3) equation: 



7u-5+2(4u+5)=-3(u+3)

We move all terms to the left:

7u-5+2(4u+5)-(-3(u+3))=0

We multiply parentheses

7u+8u-(-3(u+3))+10-5=0



We calculate terms in parentheses: -(-3(u+3)), so:

-3(u+3)

We multiply parentheses

-3u-9

Back to the equation:

-(-3u-9)



We add all the numbers together, and all the variables

15u-(-3u-9)+5=0

We get rid of parentheses

15u+3u+9+5=0

We add all the numbers together, and all the variables

18u+14=0

We move all terms containing u to the left, all other terms to the right

18u=-14

u=-14/18

u=-7/9

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