7u-7+2(3u+1)=-2(u+5)

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Solution for 7u-7+2(3u+1)=-2(u+5) equation: 



7u-7+2(3u+1)=-2(u+5)

We move all terms to the left:

7u-7+2(3u+1)-(-2(u+5))=0

We multiply parentheses

7u+6u-(-2(u+5))+2-7=0



We calculate terms in parentheses: -(-2(u+5)), so:

-2(u+5)

We multiply parentheses

-2u-10

Back to the equation:

-(-2u-10)



We add all the numbers together, and all the variables

13u-(-2u-10)-5=0

We get rid of parentheses

13u+2u+10-5=0

We add all the numbers together, and all the variables

15u+5=0

We move all terms containing u to the left, all other terms to the right

15u=-5

u=-5/15

u=-1/3

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