7u-8+2(3u+4)=-2(u+3)

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Solution for 7u-8+2(3u+4)=-2(u+3) equation: 



7u-8+2(3u+4)=-2(u+3)

We move all terms to the left:

7u-8+2(3u+4)-(-2(u+3))=0

We multiply parentheses

7u+6u-(-2(u+3))+8-8=0



We calculate terms in parentheses: -(-2(u+3)), so:

-2(u+3)

We multiply parentheses

-2u-6

Back to the equation:

-(-2u-6)



We add all the numbers together, and all the variables

13u-(-2u-6)=0

We get rid of parentheses

13u+2u+6=0

We add all the numbers together, and all the variables

15u+6=0

We move all terms containing u to the left, all other terms to the right

15u=-6

u=-6/15

u=-2/5

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