If it's not what You are looking for type in the equation solver your own equation and let us solve it.
7v+23=2(v-1)
We move all terms to the left:
7v+23-(2(v-1))=0
We calculate terms in parentheses: -(2(v-1)), so:We get rid of parentheses
2(v-1)
We multiply parentheses
2v-2
Back to the equation:
-(2v-2)
7v-2v+2+23=0
We add all the numbers together, and all the variables
5v+25=0
We move all terms containing v to the left, all other terms to the right
5v=-25
v=-25/5
v=-5
| 7c+5=4c-10 | | 8x+8-9x=2-x-15 | | -v+163=81 | | x12=14 | | x-27+x+54=180 | | 3x-10=2(4x-5 | | 236=34-w | | 5y+8=3y+28 | | x-27+54=180 | | 236=24-w | | j/3=-15 | | X+3=8x8 | | 20-(3x-9)-2=-(-11x+10 | | 3x-(5x+7)=2x | | -5v+25=5v-15 | | 17/3=u/10 | | -(5v+1)=+7v | | z-6=-8 | | 20-(3x-9)-2=-(-11x | | 13x+2x=90 | | (-9x+15)=33 | | 27.4=x47.8 | | (-9x+15)=2 | | 4c+c=675 | | 270+0.02=0.06+x | | 3×3y=30 | | -11+(b+)=7 | | 3(x+4)+x=2x+18 | | 270+0.02x=0.06 | | 4(7x-1)=-1 | | -2x^2-2=-52 | | -11+9(b+)=7 |