7v+29=5(v+3)

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Solution for 7v+29=5(v+3) equation: 



7v+29=5(v+3)

We move all terms to the left:

7v+29-(5(v+3))=0



We calculate terms in parentheses: -(5(v+3)), so:

5(v+3)

We multiply parentheses

5v+15

Back to the equation:

-(5v+15)



We get rid of parentheses

7v-5v-15+29=0

We add all the numbers together, and all the variables

2v+14=0

We move all terms containing v to the left, all other terms to the right

2v=-14

v=-14/2

v=-7

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