7v-29=4(1+5v)-2v

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Solution for 7v-29=4(1+5v)-2v equation: 



7v-29=4(1+5v)-2v

We move all terms to the left:

7v-29-(4(1+5v)-2v)=0

We add all the numbers together, and all the variables

7v-(4(5v+1)-2v)-29=0



We calculate terms in parentheses: -(4(5v+1)-2v), so:

4(5v+1)-2v

We add all the numbers together, and all the variables

-2v+4(5v+1)

We multiply parentheses

-2v+20v+4

We add all the numbers together, and all the variables

18v+4

Back to the equation:

-(18v+4)



We get rid of parentheses

7v-18v-4-29=0

We add all the numbers together, and all the variables

-11v-33=0

We move all terms containing v to the left, all other terms to the right

-11v=33

v=33/-11

v=-3

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