7v-29=5(v-3)

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Solution for 7v-29=5(v-3) equation: 



7v-29=5(v-3)

We move all terms to the left:

7v-29-(5(v-3))=0



We calculate terms in parentheses: -(5(v-3)), so:

5(v-3)

We multiply parentheses

5v-15

Back to the equation:

-(5v-15)



We get rid of parentheses

7v-5v+15-29=0

We add all the numbers together, and all the variables

2v-14=0

We move all terms containing v to the left, all other terms to the right

2v=14

v=14/2

v=7

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