7w-3+2(4w+1)=-3(w+1)

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Solution for 7w-3+2(4w+1)=-3(w+1) equation: 



7w-3+2(4w+1)=-3(w+1)

We move all terms to the left:

7w-3+2(4w+1)-(-3(w+1))=0

We multiply parentheses

7w+8w-(-3(w+1))+2-3=0



We calculate terms in parentheses: -(-3(w+1)), so:

-3(w+1)

We multiply parentheses

-3w-3

Back to the equation:

-(-3w-3)



We add all the numbers together, and all the variables

15w-(-3w-3)-1=0

We get rid of parentheses

15w+3w+3-1=0

We add all the numbers together, and all the variables

18w+2=0

We move all terms containing w to the left, all other terms to the right

18w=-2

w=-2/18

w=-1/9

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