7w2+3w-7=0

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Solution for 7w2+3w-7=0 equation: 



7w^2+3w-7=0

a = 7; b = 3; c = -7;
Δ = b2-4ac
Δ = 32-4·7·(-7)
Δ = 205
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{205}}{2*7}=\frac{-3-\sqrt{205}}{14}
$


$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{205}}{2*7}=\frac{-3+\sqrt{205}}{14}
$

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