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7x(2x+3)-8x=10x+3x
We move all terms to the left:
7x(2x+3)-8x-(10x+3x)=0
We add all the numbers together, and all the variables
7x(2x+3)-8x-(+13x)=0
We add all the numbers together, and all the variables
-8x+7x(2x+3)-(+13x)=0
We multiply parentheses
14x^2-8x+21x-(+13x)=0
We get rid of parentheses
14x^2-8x+21x-13x=0
We add all the numbers together, and all the variables
14x^2=0
a = 14; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·14·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{28}=0$
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