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7x(2x+4)=665
We move all terms to the left:
7x(2x+4)-(665)=0
We multiply parentheses
14x^2+28x-665=0
a = 14; b = 28; c = -665;
Δ = b2-4ac
Δ = 282-4·14·(-665)
Δ = 38024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{38024}=\sqrt{196*194}=\sqrt{196}*\sqrt{194}=14\sqrt{194}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-14\sqrt{194}}{2*14}=\frac{-28-14\sqrt{194}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+14\sqrt{194}}{2*14}=\frac{-28+14\sqrt{194}}{28} $
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