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7x(2x+5)=714
We move all terms to the left:
7x(2x+5)-(714)=0
We multiply parentheses
14x^2+35x-714=0
a = 14; b = 35; c = -714;
Δ = b2-4ac
Δ = 352-4·14·(-714)
Δ = 41209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{41209}=203$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-203}{2*14}=\frac{-238}{28} =-8+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+203}{2*14}=\frac{168}{28} =6 $
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