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7x(2x-2)=14
We move all terms to the left:
7x(2x-2)-(14)=0
We multiply parentheses
14x^2-14x-14=0
a = 14; b = -14; c = -14;
Δ = b2-4ac
Δ = -142-4·14·(-14)
Δ = 980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{980}=\sqrt{196*5}=\sqrt{196}*\sqrt{5}=14\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14\sqrt{5}}{2*14}=\frac{14-14\sqrt{5}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14\sqrt{5}}{2*14}=\frac{14+14\sqrt{5}}{28} $
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