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7x(3x+18)=0
We multiply parentheses
21x^2+126x=0
a = 21; b = 126; c = 0;
Δ = b2-4ac
Δ = 1262-4·21·0
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15876}=126$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(126)-126}{2*21}=\frac{-252}{42} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(126)+126}{2*21}=\frac{0}{42} =0 $
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