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7x(3x+4)=924
We move all terms to the left:
7x(3x+4)-(924)=0
We multiply parentheses
21x^2+28x-924=0
a = 21; b = 28; c = -924;
Δ = b2-4ac
Δ = 282-4·21·(-924)
Δ = 78400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{78400}=280$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-280}{2*21}=\frac{-308}{42} =-7+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+280}{2*21}=\frac{252}{42} =6 $
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