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7x(3x+5)=700
We move all terms to the left:
7x(3x+5)-(700)=0
We multiply parentheses
21x^2+35x-700=0
a = 21; b = 35; c = -700;
Δ = b2-4ac
Δ = 352-4·21·(-700)
Δ = 60025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{60025}=245$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-245}{2*21}=\frac{-280}{42} =-6+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+245}{2*21}=\frac{210}{42} =5 $
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