7x(4+2)=1+(x-2)

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Solution for 7x(4+2)=1+(x-2) equation: 



7x(4+2)=1+(x-2)

We move all terms to the left:

7x(4+2)-(1+(x-2))=0

We add all the numbers together, and all the variables

7x6-(1+(x-2))=0

We add all the numbers together, and all the variables

7x^6-(1+(x-2))=0



We calculate terms in parentheses: -(1+(x-2)), so:

1+(x-2)

determiningTheFunctionDomain
(x-2)+1

We get rid of parentheses

x-2+1

We add all the numbers together, and all the variables

x-1

Back to the equation:

-(x-1)



We do not support expression: x^6

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