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7x(4x+5)=340
We move all terms to the left:
7x(4x+5)-(340)=0
We multiply parentheses
28x^2+35x-340=0
a = 28; b = 35; c = -340;
Δ = b2-4ac
Δ = 352-4·28·(-340)
Δ = 39305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{39305}}{2*28}=\frac{-35-\sqrt{39305}}{56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{39305}}{2*28}=\frac{-35+\sqrt{39305}}{56} $
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