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7x(6x+7)=-3
We move all terms to the left:
7x(6x+7)-(-3)=0
We add all the numbers together, and all the variables
7x(6x+7)+3=0
We multiply parentheses
42x^2+49x+3=0
a = 42; b = 49; c = +3;
Δ = b2-4ac
Δ = 492-4·42·3
Δ = 1897
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{1897}}{2*42}=\frac{-49-\sqrt{1897}}{84} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{1897}}{2*42}=\frac{-49+\sqrt{1897}}{84} $
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