7x(6x-8)=0

Solution for 7x(6x-8)=0 equation:

7x(6x-8)=0

We multiply parentheses

42x^2-56x=0

a = 42; b = -56; c = 0;
Δ = b2-4ac
Δ = -562-4·42·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-56}{2*42}=\frac{0}{84}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+56}{2*42}=\frac{112}{84}
=1+1/3
$