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7x(9x+8)=40
We move all terms to the left:
7x(9x+8)-(40)=0
We multiply parentheses
63x^2+56x-40=0
a = 63; b = 56; c = -40;
Δ = b2-4ac
Δ = 562-4·63·(-40)
Δ = 13216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13216}=\sqrt{16*826}=\sqrt{16}*\sqrt{826}=4\sqrt{826}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-4\sqrt{826}}{2*63}=\frac{-56-4\sqrt{826}}{126} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+4\sqrt{826}}{2*63}=\frac{-56+4\sqrt{826}}{126} $
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