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7x(x+2)=6x(x+15)
We move all terms to the left:
7x(x+2)-(6x(x+15))=0
We multiply parentheses
7x^2+14x-(6x(x+15))=0
We calculate terms in parentheses: -(6x(x+15)), so:We get rid of parentheses
6x(x+15)
We multiply parentheses
6x^2+90x
Back to the equation:
-(6x^2+90x)
7x^2-6x^2+14x-90x=0
We add all the numbers together, and all the variables
x^2-76x=0
a = 1; b = -76; c = 0;
Δ = b2-4ac
Δ = -762-4·1·0
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5776}=76$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-76}{2*1}=\frac{0}{2} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+76}{2*1}=\frac{152}{2} =76 $
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