7x(x+3)=(x)(7x-3)+36

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Solution for 7x(x+3)=(x)(7x-3)+36 equation: 



7x(x+3)=(x)(7x-3)+36

We move all terms to the left:

7x(x+3)-((x)(7x-3)+36)=0

We multiply parentheses

7x^2+21x-(x(7x-3)+36)=0



We calculate terms in parentheses: -(x(7x-3)+36), so:

x(7x-3)+36

We multiply parentheses

7x^2-3x+36

Back to the equation:

-(7x^2-3x+36)



We get rid of parentheses

7x^2-7x^2+21x+3x-36=0

We add all the numbers together, and all the variables

24x-36=0

We move all terms containing x to the left, all other terms to the right

24x=36

x=36/24

x=1+1/2

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