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7x(x+3)=(x)(7x-3)+36
We move all terms to the left:
7x(x+3)-((x)(7x-3)+36)=0
We multiply parentheses
7x^2+21x-(x(7x-3)+36)=0
We calculate terms in parentheses: -(x(7x-3)+36), so:We get rid of parentheses
x(7x-3)+36
We multiply parentheses
7x^2-3x+36
Back to the equation:
-(7x^2-3x+36)
7x^2-7x^2+21x+3x-36=0
We add all the numbers together, and all the variables
24x-36=0
We move all terms containing x to the left, all other terms to the right
24x=36
x=36/24
x=1+1/2
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