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7x(x-1)=x-1
We move all terms to the left:
7x(x-1)-(x-1)=0
We multiply parentheses
7x^2-7x-(x-1)=0
We get rid of parentheses
7x^2-7x-x+1=0
We add all the numbers together, and all the variables
7x^2-8x+1=0
a = 7; b = -8; c = +1;
Δ = b2-4ac
Δ = -82-4·7·1
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-6}{2*7}=\frac{2}{14} =1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+6}{2*7}=\frac{14}{14} =1 $
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