7x(x-3)-4(x-3)=0

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Solution for 7x(x-3)-4(x-3)=0 equation:



7x(x-3)-4(x-3)=0
We multiply parentheses
7x^2-21x-4x+12=0
We add all the numbers together, and all the variables
7x^2-25x+12=0
a = 7; b = -25; c = +12;
Δ = b2-4ac
Δ = -252-4·7·12
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-17}{2*7}=\frac{8}{14} =4/7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+17}{2*7}=\frac{42}{14} =3 $

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