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7x(x-4)=5(x-2)
We move all terms to the left:
7x(x-4)-(5(x-2))=0
We multiply parentheses
7x^2-28x-(5(x-2))=0
We calculate terms in parentheses: -(5(x-2)), so:We get rid of parentheses
5(x-2)
We multiply parentheses
5x-10
Back to the equation:
-(5x-10)
7x^2-28x-5x+10=0
We add all the numbers together, and all the variables
7x^2-33x+10=0
a = 7; b = -33; c = +10;
Δ = b2-4ac
Δ = -332-4·7·10
Δ = 809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-\sqrt{809}}{2*7}=\frac{33-\sqrt{809}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+\sqrt{809}}{2*7}=\frac{33+\sqrt{809}}{14} $
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