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7x(x-6)=28
We move all terms to the left:
7x(x-6)-(28)=0
We multiply parentheses
7x^2-42x-28=0
a = 7; b = -42; c = -28;
Δ = b2-4ac
Δ = -422-4·7·(-28)
Δ = 2548
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2548}=\sqrt{196*13}=\sqrt{196}*\sqrt{13}=14\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-14\sqrt{13}}{2*7}=\frac{42-14\sqrt{13}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+14\sqrt{13}}{2*7}=\frac{42+14\sqrt{13}}{14} $
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