7x*(5x-2)=0

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Solution for 7x*(5x-2)=0 equation:



7x(5x-2)=0
We multiply parentheses
35x^2-14x=0
a = 35; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·35·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*35}=\frac{0}{70} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*35}=\frac{28}{70} =2/5 $

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