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7x*7x-2x-2x-3=0
We add all the numbers together, and all the variables
-4x+7x*7x-3=0
Wy multiply elements
49x^2-4x-3=0
a = 49; b = -4; c = -3;
Δ = b2-4ac
Δ = -42-4·49·(-3)
Δ = 604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{604}=\sqrt{4*151}=\sqrt{4}*\sqrt{151}=2\sqrt{151}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{151}}{2*49}=\frac{4-2\sqrt{151}}{98} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{151}}{2*49}=\frac{4+2\sqrt{151}}{98} $
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