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7x*8x=(5x+3)(10x-2)
We move all terms to the left:
7x*8x-((5x+3)(10x-2))=0
Wy multiply elements
56x^2-((5x+3)(10x-2))=0
We multiply parentheses ..
56x^2-((+50x^2-10x+30x-6))=0
We calculate terms in parentheses: -((+50x^2-10x+30x-6)), so:We get rid of parentheses
(+50x^2-10x+30x-6)
We get rid of parentheses
50x^2-10x+30x-6
We add all the numbers together, and all the variables
50x^2+20x-6
Back to the equation:
-(50x^2+20x-6)
56x^2-50x^2-20x+6=0
We add all the numbers together, and all the variables
6x^2-20x+6=0
a = 6; b = -20; c = +6;
Δ = b2-4ac
Δ = -202-4·6·6
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-16}{2*6}=\frac{4}{12} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+16}{2*6}=\frac{36}{12} =3 $
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