7x+1(2x+1)=5x-7(7x-5)

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Solution for 7x+1(2x+1)=5x-7(7x-5) equation: 



7x+1(2x+1)=5x-7(7x-5)

We move all terms to the left:

7x+1(2x+1)-(5x-7(7x-5))=0



We calculate terms in parentheses: -(5x-7(7x-5)), so:

5x-7(7x-5)

We multiply parentheses

5x-49x+35

We add all the numbers together, and all the variables

-44x+35

Back to the equation:

-(-44x+35)



We get rid of parentheses

7x+1(2x+1)+44x-35=0

We add all the numbers together, and all the variables

51x+1(2x+1)-35=0

We move all terms containing x to the left, all other terms to the right

51x+1(2x+1)=35

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