7x+1/2(4x-5)=3/2+2(x-3)

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Solution for 7x+1/2(4x-5)=3/2+2(x-3) equation: 



7x+1/2(4x-5)=3/2+2(x-3)

We move all terms to the left:

7x+1/2(4x-5)-(3/2+2(x-3))=0



Domain of the equation: 2(4x-5)!=0

x∈R





Domain of the equation: 2+2(x-3))!=0

We move all terms containing x to the left, all other terms to the right

2(x-3))!=-2

x∈R



We calculate fractions


7x+(2(x-3))+1*2)/18x+(-6x4/18x=0



We calculate terms in parentheses: +(2(x-3)), so:

2(x-3)

We multiply parentheses

2x-6

Back to the equation:

+(2x-6)



We get rid of parentheses

7x+2x+1*2)/18x+(-6x4/18x-6=0

We calculate fractions

We do not support expression: x^5

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