7x+100-2x=3(x-40)

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Solution for 7x+100-2x=3(x-40) equation: 



7x+100-2x=3(x-40)

We move all terms to the left:

7x+100-2x-(3(x-40))=0

We add all the numbers together, and all the variables

5x-(3(x-40))+100=0



We calculate terms in parentheses: -(3(x-40)), so:

3(x-40)

We multiply parentheses

3x-120

Back to the equation:

-(3x-120)



We get rid of parentheses

5x-3x+120+100=0

We add all the numbers together, and all the variables

2x+220=0

We move all terms containing x to the left, all other terms to the right

2x=-220

x=-220/2

x=-110

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