7x+12-5x=4(2x-3)+48

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Solution for 7x+12-5x=4(2x-3)+48 equation: 



7x+12-5x=4(2x-3)+48

We move all terms to the left:

7x+12-5x-(4(2x-3)+48)=0

We add all the numbers together, and all the variables

2x-(4(2x-3)+48)+12=0



We calculate terms in parentheses: -(4(2x-3)+48), so:

4(2x-3)+48

We multiply parentheses

8x-12+48

We add all the numbers together, and all the variables

8x+36

Back to the equation:

-(8x+36)



We get rid of parentheses

2x-8x-36+12=0

We add all the numbers together, and all the variables

-6x-24=0

We move all terms containing x to the left, all other terms to the right

-6x=24

x=24/-6

x=-4

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