7x+14/7+3=7(x+2)/7

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Solution for 7x+14/7+3=7(x+2)/7 equation: 



7x+14/7+3=7(x+2)/7

We move all terms to the left:

7x+14/7+3-(7(x+2)/7)=0

We add all the numbers together, and all the variables

7x-(7(x+2)/7)+5=0

We multiply all the terms by the denominator


7x*7)-(7(x+2)+5*7)=0

We add all the numbers together, and all the variables

7x*7)-(7(x+2)=0

Wy multiply elements

49x^2=0

a = 49; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·49·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{98}=0$

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