7x+15=2(x-5)+41

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Solution for 7x+15=2(x-5)+41 equation: 



7x+15=2(x-5)+41

We move all terms to the left:

7x+15-(2(x-5)+41)=0



We calculate terms in parentheses: -(2(x-5)+41), so:

2(x-5)+41

We multiply parentheses

2x-10+41

We add all the numbers together, and all the variables

2x+31

Back to the equation:

-(2x+31)



We get rid of parentheses

7x-2x-31+15=0

We add all the numbers together, and all the variables

5x-16=0

We move all terms containing x to the left, all other terms to the right

5x=16

x=16/5

x=3+1/5

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