7x+18=((10x+5)+(8x-1))/2

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Solution for 7x+18=((10x+5)+(8x-1))/2 equation: 



7x+18=((10x+5)+(8x-1))/2

We move all terms to the left:

7x+18-(((10x+5)+(8x-1))/2)=0

We multiply all the terms by the denominator


7x*2)-(((10x+5)+(8x-1))+18*2)=0

We add all the numbers together, and all the variables

7x*2)-(((10x+5)+(8x-1))=0

Wy multiply elements

14x^2=0

a = 14; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·14·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{28}=0$

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